Tolong beserta caranya
Penjelasan dengan langkah-langkah:
[tex] {3}^{2x - 3} - 4( {3}^{x - 2} ) + 1 = 0 \\ \frac{ {3}^{2x} }{ {3}^{3} } - 4( \frac{ {3}^{x} }{ {3}^{2} }) + 1 = 0 \\ \frac{ { ({3}^{x}) }^{2} }{27} - 4( \frac{ {3}^{x} }{9} ) + 1 = 0 \\ \\ misal \: {3}^{x} = y \\ \\ \frac{1}{27} {y}^{2} - \frac{4}{9} y + 1 = 0 \: (semua \: dikalikan \: 27) \\ {y}^{2} - 12y + 27 = 0 \\ (y - 9)(y - 3) = 0 \\ y = 9 \: atau \: y = 3 \\ {3}^{x} = 9 \: atau \: {3}^{x} = 3 \\ {3}^{x} = {3}^{2} \: atau \: {3}^{x} = {3}^{1} \\ x = 2 \: atau \: x = 1 [/tex]
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